35p^2=9p+56

Solution for 35p^2=9p+56 equation:

35p^2=9p+56

We move all terms to the left:

35p^2-(9p+56)=0

We get rid of parentheses

35p^2-9p-56=0

a = 35; b = -9; c = -56;
Δ = b2-4ac
Δ = -92-4·35·(-56)
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7921}=89$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-89}{2*35}=\frac{-80}{70}
=-1+1/7
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+89}{2*35}=\frac{98}{70}
=1+2/5
$